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Mathematics 9 Online
skrtkobainn:

i need help

skrtkobainn:

2. Describe the shape of the cross section when the box is cut parallel to the base.

skrtkobainn:

my measurements are length = 8in. width=5in. Height=1in.

MidNiGhtSkY:

it's a Triangle right?

skrtkobainn:

no rectangle

MidNiGhtSkY:

you finding the area?

MidNiGhtSkY:

if its a rectangle, then that should be the answer-

MidNiGhtSkY:

is it like a cube? a 3d model?

Roney:

there are 2 simple basic rules A cross section that is parallel to the base is a hexagon congruent to the hexagonal bases. A cross section that is perpendicular to the base is a rectangle. in your case, the right answer is the second one

HaydenwH:

so if u cut it parallel to the base ur basically cutting the height in half correct?

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MidNiGhtSkY:

that doesnt make since roney

Roney:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @MidNiGhtSkY that doesnt make since roney \(\color{#0cbb34}{\text{End of Quote}}\) what do you mean?

MidNiGhtSkY:

your post- :>

MidNiGhtSkY:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @skrtkobainn my measurements are length = 8in. width=5in. Height=1in. \(\color{#0cbb34}{\text{End of Quote}}\) are these measurements before or after you cut the box?

HaydenwH:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @MidNiGhtSkY \(\color{#0cbb34}{\text{Originally Posted by}}\) @skrtkobainn my measurements are length = 8in. width=5in. Height=1in. \(\color{#0cbb34}{\text{End of Quote}}\) are these measurements before or after you cut the box? \(\color{#0cbb34}{\text{End of Quote}}\) i think these are the original measurments

Mudasir:

A rectangle is a 2D shape in geometry, having 4 sides and 4 corners. Its two sides meet at right angles. Thus, a rectangle has 4 angles, each measuring 90 ̊.

MidNiGhtSkY:

alright, i was just wondering it so i know how to help, Mudasir

HaydenwH:

im gone because more help is needed here than i can give

Mudasir:

Ok solve now\(\color{#0cbb34}{\text{Originally Posted by}}\) @MidNiGhtSkY \(\color{#0cbb34}{\text{Originally Posted by}}\) @Mudasir \(\color{#0cbb34}{\text{Originally Posted by}}\) @MidNiGhtSkY alright, i was just wondering it so i know how to help, Mudasir \(\color{#0cbb34}{\text{End of Quote}}\) Really \(\color{#0cbb34}{\text{End of Quote}}\) yea, it wasn't really making sense to me \(\color{#0cbb34}{\text{End of Quote}}\) Ok solve now

MidNiGhtSkY:

i can try but i don't know if that was the beginning measurements or after they cut it

Mudasir:

Area=length × width

skrtkobainn:

those were the beginning measement

Mudasir:

Area of the rectangle, A = L × B A = L \times B A=L×B. Area of the square, A = S i d e 2 =Side ^2 =Side2. Perimeter of a rectangle, P = 2 × ( L + B ) P = 2 \times ( L+B ) P=2×(L+B)

MidNiGhtSkY:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @skrtkobainn those were the beginning measement \(\color{#0cbb34}{\text{End of Quote}}\) are you trying to find the area? surface area? or perimeter?

skrtkobainn:

2. Describe the shape of the cross section when the box is cut parallel to the base.

MidNiGhtSkY:

the box is a cube right? and a cube is a square shape supposedly? so if you cut it what should it be?

skrtkobainn:

so the thing i measured is a rectangle

MidNiGhtSkY:

mhm

MidNiGhtSkY:

and if you cut the rectangle like your cutting a slice of cheese it would be.

Mudasir:

12 is right answer

MidNiGhtSkY:

she is finding the shape, 12 isn't a shape.

Mudasir:

Ok shape

skrtkobainn:

would it be a square?

Mudasir:

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HaydenwH:

wait why is the cut diagonal?

MidNiGhtSkY:

your doing it parallel right?

HaydenwH:

i thought it had to be parallel to the base?

MidNiGhtSkY:

it's parrellel

HaydenwH:

as i posted earlier in the question

MidNiGhtSkY:

:I i need to spell correct, and it's parallel. i scrolled to check :)

HaydenwH:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @HaydenwH so if u cut it parallel to the base ur basically cutting the height in half correct? \(\color{#0cbb34}{\text{End of Quote}}\)

HaydenwH:

1 attachment
skrtkobainn:

triangle if its cut diagonally?

Mudasir:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @MidNiGhtSkY your doing it parallel right? \(\color{#0cbb34}{\text{End of Quote}}\) Yes

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