Question

Solve *will post equation* , where is a real number.
Simplify your answer as much as possible.

If there is more than one solution, separate them with commas.
If there is no solution, click on "No solution".

Answer 1

@snowflake0531 @jhonyy9

Answer 2

Where is the equation?

Answer 3

Toast... sorry: \[w^2=36\]

Answer 4

\[w^{2} = 36 \]

\[w_{1,2} = \sqrt{36}\]

Answer 5

hope you know 36 = 6*6 = 6^2

any idea now ?

Answer 6

exponets? or sqauring..?

Answer 7

\[w^{2} = 36 = 6^{2}\]
\[w_{1,2}= \sqrt{6^{2}}= +/- ?\]

Answer 8

or an other way

\[\sqrt{6^{2}}= +/- \left( 6^{2} \right)^\frac{ 1 }{ 2 } = ?\]

Answer 9

6,-6?

Answer 10

perfect

Answer 11

questions ?

Answer 12

no sir thank you :)

Answer 13

np

anytime

yw