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M ‹ A = 100-x m < B = 80+x m < C = 110-3x m < D = 75+2x Quadrilateral ABCD is a parallelogram if both pairs of opposite angles are equal. Prove that quadrilateral ABCD is a parallelogram by finding the value of x.
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so opposite angles are equal that means angle A = angle C angle B = angle D
angle A is 100 - x angle C is 110 - 3x so set them equal to each other and solve for x 100 - x = 110 - 3x
5
Good! And similarly angle B = angle D 80 + x = 75 + 2x
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Same thing
Exactly! So we found the value of x to prove that the quadrilateral is a parallelogram
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