Question

factor the trinomial. 6x^2 + x - 40

Answer 1

do you can calcule the roots of this quadratic ?

Answer 2

P(x)= ax^2 +bx +c
and x_1 , x_2 the roots of P(x)
so in this case you can write

P(x) = a(x - x_1)(x - x_2) the factorized form

Answer 3

What grade is this?/

Answer 4

\(\color{#0cbb34}{\text{Originally Posted by}}\) @surjithayer
product of 6 and -40=-240
16-15=1
\[16\times15=-240\]
\[6x^2+x-40\]
\[=6x^2+(16-15)x-40\]
\[=6x^2+16x-15x-40\]
=2x(3x+8)-5(3x+8)
=(3x+8)(2x-5)
\(\color{#0cbb34}{\text{End of Quote}}\)