If the preimage B(0, -5) were translated down 3, and right 1, which point would represent the image?
B'(-3, -4) B'(1, -8) B'(3, -4) B'(-1, -2)
have you tried drawing it? it sometimes helps to have a physical image of it.
Ain’t no pic
basically tho so your x values are right to left while y values are up and down. so for this its going down 3 on your y-axis and right 1 on your x-axis. so take your preimage B(0,-5) and minus 3 from your y value (-5) and add 1 to your x value (0)
-8
And 1
your going to want to keep it in (x,y) so here i'll draw it out. it may help |dw:1616093750137:dw|
1, -8
yes
You are correct. Good job.
\(\color{#0cbb34}{\text{Originally Posted by}}\) @QuestionCoveBot You are correct. Good job. \(\color{#0cbb34}{\text{End of Quote}}\) Thanks
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Shaypop \(\color{#0cbb34}{\text{Originally Posted by}}\) @QuestionCoveBot You are correct. Good job. \(\color{#0cbb34}{\text{End of Quote}}\) Thanks \(\color{#0cbb34}{\text{End of Quote}}\) Thank Honda, not me.
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