Help me plz!!!! This problem is on another level and my brain cells are dying.
@jhonyy9 or @AZ can yall help ah42632?
I think that you could just use SAS, to prove that all the triangles are similar, and because they are all similar, their sides are equal, which makes the intersecting points the midpoint
one problem with that. Idk how to use any of those equations or anything like that to solve these kind of problems
There aren't any equations It's to the left2a, to the right 2a 2a = 2a So the lengths are equal Same with the y axis 2b = 2b, the lengths are equal
I'm actually confused, because I think it's actually much easier than what you think of it to be? like a=a, 2a=2a?
Well either way i have no clue in the world how to solve this problem or explain it. Srry....
It's to the left 2a, to the right 2a 2a = 2a So the lengths are equal Same with the y axis 2b = 2b, the lengths are equal Think of it like, 2 times a is just 2a, so bc it's the same distance, they're equal
ok. Getting a hang of it now. watching a youtube video too. Thx for starting me off on it. It helped understand the video better too.
:) yw~!
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