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snowflake0531:
\(\color{#0cbb34}{\text{Originally Posted by}}\) @cseltzer
6
\(\color{#0cbb34}{\text{End of Quote}}\)
wrong
cseltzer:
haha
snowflake0531:
So, first, we know that we can ignore the numbers, the -6 and 7, because the other half of the equation already got 1
All we need to know is
___ + 2x = -4x
snowflake0531:
y+ 2x= -4x
What is y
cseltzer:
-6 maybe
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snowflake0531:
Firstly, wrong again
secondly, shut it
cseltzer:
lol
snowflake0531:
:)
Countrygirl123:
its -6x right not because cseltzer said
snowflake0531:
Yep, it's -6x
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cseltzer:
told ya
snowflake0531:
it's not -6, it's -6x
so, ur still wrong cseltzer
cseltzer:
:(
Countrygirl123:
ha
snowflake0531:
:(
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cseltzer:
close
snowflake0531:
not rly
Countrygirl123:
so i put -6x in the box
snowflake0531:
yes
now b?
cseltzer:
si
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( a^2 + ___ + 1) - (___ + 5a + ___) = 4a^2 -2a + 7
By the way, remember that it's subtracting the whole expression of (___+5a+___)
Countrygirl123:
ok
snowflake0531:
So, let's first do the ^2 ones, the square ones
We have a^2 - (____) = 4a^2
What is ____
snowflake0531:
Remember that 2 negatives equal a positive
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Countrygirl123:
\[3a ^{2}\]
snowflake0531:
Actually, but we need to subtract something
So, it's -3a^2, instead
Countrygirl123:
ok
snowflake0531:
( a^2 + ___ + 1) - (3a^2 + 5a + ___) = 4a^2 -2a + 7
And to make it less confusing, we can just delete those that are made equal
(__+1) - (5a + ___) = -2a+7
snowflake0531:
So
__-5a = -2a
what is __
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Countrygirl123:
3a
snowflake0531:
Yep
So now we have
(3a+1) - (5a + ___) = -2a+7
And deleting those that are equal
1-___=7
find ___
Countrygirl123:
-6
snowflake0531:
Yep, so now you have all of your values
Countrygirl123:
ok thank you
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