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another factoring
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@snowflake0531
What to the third power is 1
1
Yep, so \[27x^3 + 1^3\]
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So, in this case, put 'x' as 27x, and put 'y' as 1
so would it be (3x)^3 + 1^3, right?
Well, that depends on the teacher, does the teacher mean (27)^3 or 27(x^3) idek
thats part of the notes
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Okay, then you're right
thx
yw
@boredfr
wat are you doing
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They turned off dms
So I mentioned em
So I could tell em to turn dms on
......
Lmao, big brain
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First time I checked my notifs in an hour
Lmao
Snap
Yes please talk to each other elsewhere and not spam my notifs xd
Ight
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