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-12? @AZ
no, remember f(x) is y \( f^{-1}(x)\) is the inverse
3?
so basically yup!
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so \( f^{-1}(-6)\) says that -6 of the INVERSE function -6 is the x-value of the inverse function that means -6 is going to be the y-value of the normal function
so y-value of the inverse function is going to be the x-value of the normal function
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