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Chris obtains a z-score of +1.5. The standard deviation in the sample is 12 and Chris’s raw score is 78, so what is the sample’s mean?
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From the link above: In these case, the z-score is \[ z={x-{\bar {x}} \over S}\] where: \( \bar {x}\) is the mean of the sample. S is the standard deviation of the sample.
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