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Mathematics 7 Online
jnlkmnjkm:

math problem

jnlkmnjkm:

1 attachment
AZ:

Very similar to last time what are the x-intercepts? where does it cross the x-axis

jnlkmnjkm:

1 4

AZ:

so how would you write that if x = 1 and x = 4

jnlkmnjkm:

(x+1)(x+4)

AZ:

No, you got it switched again x = 1 x - 1 =1 - 1 x -1 = 0 (x-1) would be one of the factors of the equation what about if x = 4

JamesTerry:

oof already answered

jnlkmnjkm:

(x-1) (x-4)

jnlkmnjkm:

az

jnlkmnjkm:

@AZ

AZ:

yes so we have y = a(x-1)(x-4) and we need to find out what 'a' is and on your graph, you see the point (0, -4) so plug that in -4 = a(0-1)(0-4) what is 0 - 1 = what is 0 - 4 =

jnlkmnjkm:

-1 -4

AZ:

yes so we have -4 = a * -1 * -4 what is -1 * -4 = ?? and then solve for a

jnlkmnjkm:

a=-1

AZ:

exactly so now we have y = -1(x-1)(x-4) can you simplify that?

jnlkmnjkm:

-x^2+5x-4

jnlkmnjkm:

az

AZ:

that's correct

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