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Very similar to last time what are the x-intercepts? where does it cross the x-axis
1 4
so how would you write that if x = 1 and x = 4
(x+1)(x+4)
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No, you got it switched again x = 1 x - 1 =1 - 1 x -1 = 0 (x-1) would be one of the factors of the equation what about if x = 4
oof already answered
(x-1) (x-4)
az
@AZ
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yes so we have y = a(x-1)(x-4) and we need to find out what 'a' is and on your graph, you see the point (0, -4) so plug that in -4 = a(0-1)(0-4) what is 0 - 1 = what is 0 - 4 =
-1 -4
yes so we have -4 = a * -1 * -4 what is -1 * -4 = ?? and then solve for a
a=-1
exactly so now we have y = -1(x-1)(x-4) can you simplify that?
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-x^2+5x-4
az
that's correct
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