math problem
@jhonyy9
so the width let note an x and the length an y in this way without wall we have 2 width so 2x and one y in this way we can write 2x +y = 180 for area A = x*y so you need calcule the x and y to get the maxim area any idea now ?
how do I get x and y
for example 2*40 +100 = 180 in this case area will be 40*100 = 4000 or 2*30 + 120 = 180 in this case area is 30*120 = 3600
\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 you need find the x and y values to get the maxim area possibile \(\color{#0cbb34}{\text{End of Quote}}\)
4000 by 3600 feet
\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 no these are just examples for areas what you get for these example values of x and y \(\color{#0cbb34}{\text{End of Quote}}\)
im not sure
@supie can you pls explain here ? ty.
both of you guys left
whats step 1
@jhonyy9
you need find these values of x and y for what you get the maxim areas
can you explain in a simpler way how can I find x and y
\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 for example 2*40 +100 = 180 in this case area will be 40*100 = 4000 or 2*30 + 120 = 180 in this case area is 30*120 = 3600 \(\color{#0cbb34}{\text{End of Quote}}\) here above i ve gave you example for it
where do you get 2 and 40
how can you make 180 from 2x and 1y
4000 is x and 3600 is y
no these are just examples for areas
but how is it an example if its also 180
dont forget you need getting the x and y values with this condition 2x +y = 180
2*40 + 100 = 180
yes in this case area will be 40*100 = 4000 other values for x and y can be 2*50 +80 = 100 +80 = 180 in this case area will be 50*80 = 4000
40 is x and 100 is y
or other one 2*60 + 60 but in this case you get a square and not a rectangle - so attention please
can I use 40 and 100
\(\color{#0cbb34}{\text{Originally Posted by}}\) @klmjnmkj 40 is x and 100 is y \(\color{#0cbb34}{\text{End of Quote}}\) yes
whats the next step
if you see for x=40 and y = 100 you get area = 4000 and for x=50 and y= 80 you get area the same 4000 but what will get for x=55 ?
4400
2*55=110 so for 180 you need y = 70 in this case area = 55*70 = ?
3850
3850 what is smaller than 4000 yes ?
yep
so from this result that the maxim area will can be 4000 what you can get if x=50 and y=80 or for x=40 and y=100 ok ?
yep
questions ?
yep so its 4000 feet by ?
no 4000 is the maxim area
the feet is 50 feet by 80
fenced with 180 feet fence yes 50 feet by 80 feet or 40 feet by 100 feet
\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9 fenced with 180 feet fence yes 50 feet by 80 feet or 40 feet by 100 feet \(\color{#0cbb34}{\text{End of Quote}}\) bc. in every two cases you get area = 4000 square feet
yes ofc. for 45*90 = 4050 area and this is more than 4000
lol
do you understand now the way ?
yep
ok
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