Question

math problem

Answer 1

@AZ

Answer 2

whats step one

Answer 3

hmmm

so \(f(x) = \sqrt{x+3} -9\)

and \( f(g(x)) = x\)

that means then

\( f (g(x)) = \sqrt{g(x) + 3} - 9 = x\)

so we need to solve for g(x)

\(\sqrt{g(x) + 3} - 9 = x\)

what do you get if you add 9 to both sides?

Answer 4

my site crashed

Answer 5

9+9 and 3+9?

Answer 6

it's - 9 + 9

and 3 is under the square root so you can't do anything to it yet

and x + 9 on the other side

so simplify it

and then we want to get g(x) outside of that square root, so square both sides

and remember \((a+b)^2 = a^2 + 2ab + b^2\)