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math problem
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@snowflake0531
i can maybe
@Florisalreadytaken
is there more in this equation??
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no thats all
ok
brbr
alright
is x 10 or 6
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wait, nvm -- we dont deen to find the constant
instead, we should use this \[ y_1x_1 = y_2x_2\]
so we have \[3 \times 10 = y \times 6\]
\[6y = 30\] \[y = 5\]
3 times 10 is 30
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the anser is 5?
yes!
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