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help please(ss below)
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Take each coordinate point and do \[((x-3)3,(y-8)3)\]
so 3x * 3 8y *3?
Now first subtract 3 from x, and then multiply it with 3 Then subtract 8 from y, multiply that with 3
so x * 3 - 8?
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How about we just first do the transformation for all of them For <-3,-8> (2,2) (3,-1) (-1,-2)
how do you do that?
(2-3,2-8) (3-3,-1-8) (-1-3,-2-8)
subtraction?
Yes, just simplify them
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(-1,-6) (0,-7) (-4,-10)
?
(0,-7) is incorrect
mb (0, - 9)
are those the answers?
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no then you have to dilate them multiply each number by 3
so (-3,-18) (0,-27) (-12,-30)
?
yep so those are your coordinates
thx
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yw~
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