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Mathematics
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Secant Intersection Outside Circle
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@Az
Here's the formula
So set it up 9 * (9+12) = 3 * (3+x) Can you solve for x?
Uh second
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x = 11?
Not quite what is 9+12 = ? and on the other side of the equal sign can you distribute the 3 into the parenthesis? \( a(b+c) = ab + ac\)
21
Good, so then you have 9 * 21 = 3(x + 3) What is 9 * 21 = ?
189
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so we have 189 = 3(x+3) divide 3 on both sides so we can slowly get x all by itself 189 / 3 = x + 3 and then subtract 3 on both sides
60?
There you go!! That's your final answer :)
Hardest problem of my life
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