Question

help please

Answer 1

we have to use pythagoras theorem

Answer 2

ohhh?

Answer 3

how so?

Answer 4

AB=AC=2
\[AB \perp AC\]
\[AB^2+AC^2=BC^2\]
\[2^2+2^2=BC^2\]
\[BC=\sqrt{8}=2\sqrt{2}\]

Answer 5

nope i got it

Answer 6

BC=BD
\[BC \perp BD\]
\[BC^2+BD^2=CD^2\]
\[8+8=CD^2\]
\[CD=\sqrt{16}=4\]

Answer 7

i got it thanks tho

Answer 8

similarly you can proceed further .