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Mathematics 13 Online
rubypenaflor:

i need help on my math work! can some one please help me!!

animeobsessionn:

sure whats the question?

rubypenaflor:

okay hold on lemme get it

rubypenaflor:

1 attachment
rubypenaflor:

are you reading it? or something :)

AZ:

Welcome back

rubypenaflor:

hii how r u

AZ:

One question at a time For the first big question regarding the graph how would you find out the equation for it? it has zeros at 0 and 4 so (0, 0) and (4, 0) and it goes through the point (2, 20) which equation that's listed satisfies those three points?

animeobsessionn:

which question?

rubypenaflor:

the first one on the top left

AZ:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @AZ One question at a time For the first big question regarding the graph how would you find out the equation for it? it has zeros at 0 and 4 so (0, 0) and (4, 0) and it goes through the point (2, 20) which equation that's listed satisfies those three points? \(\color{#0cbb34}{\text{End of Quote}}\) this is for the one on the top left

rubypenaflor:

d?

AZ:

no? D says h = -4t(t-1) so we said that our graph has three points (0, 0) (4, 0) and (2, 20) plug in each one by one into the equation 0 = -4*0 * (0-1) 0 = 0 so that point works but we still have to check the other two points (4, 0) 4 is our t and 0 is our h value 0 = -4 * 4 * (4-1) 0 = -4 * 4 * 3 0 = -48 that's not true, so that point does NOT work with that equation so that means answer choice D is false

AZ:

so plug them in to the answer choice for which equation does all three points make it true

rubypenaflor:

b?

AZ:

that's correct

AZ:

Now the rest of your questions are pretty similar You can either factor the equations or you can just graph it using https://www.desmos.com/calculator the x-values where the graph crosses the x-axis is going to be the zeros of the equation

rubypenaflor:

ahh okay

rubypenaflor:

can i text you if i need help on the other ones?

rubypenaflor:

or are we gonna go over the other ones too?

AZ:

you can make a new post and tag me like @AZ

rubypenaflor:

okayy! thanks

AZ:

You're welcome!

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