when you have
ab = 0
that means the solution is a = 0 and b = 0
AZ:
So for the first one
x(x-1) = 0
\( \color{red}{a}\color{orange}{b} =0\)
then \(\color{red}{a}= 0\) and \(\color{orange}{b} =0\)
so
\(\color{red}{x}\color{orange}{(x-1)} = 0\)
set it equal to 0 and solve for x
AZ:
so x=0
this one is a given
but the second one is
x-1 = 0
so x = ??
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smurfofficial:
UHH
smurfofficial:
idk az
smurfofficial:
1-1
AZ:
add 1 to both sides, what do you get?
x -1 + 1 = 0
x - 1 + 1 = 0 + 1
x = ??
smurfofficial:
x = 0 and x = 1
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AZ:
Good now the next one
(5-x)(5+x) = 0
set each one equal to 0 and solve for x
5 - x = 0
and
5 + x = 0
what is x equal to for both?
smurfofficial:
x = 5 and -5
AZ:
Excellent!!
AZ:
Now
(2x+1)(x+8) = 0
2x + 1 = 0
x = ??
and
x + 8 = 0
x = ??
smurfofficial:
x = -1/2 and x = -8
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AZ:
Splendid!
Now
(3x-3)(3x-3) = 0
set each one equal to 0 and solve for x
smurfofficial:
x = 1
AZ:
Wonderful!
And what's the last one?
smurfofficial:
x = 7 and x = 4
AZ:
-4*
but it's your last answer choice so yes
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