Question

There is a slide in a park. One of its side Company hired one of its walls for 3 months. Walls has been painted in some colour with a message “KEEP THE PARK GREEN AND CLEAN” (see figure). If the sides of the wall are 25 m, 13 m and 8m, find the area painted in colour.

Answer 1

you have a figure inserted, right? it looks like this no?

Answer 2

No. It's the reverse of what you drew.

Answer 3

same thing lol!

so we have to use this formula first, and then use the heron's formula after

\[ S \scriptsize\text{emi perimeter} (\color{chocolate}{s}) = \frac { \color{thistle}{a} + \color{royalblue}{b}+ \color{palegreen}{c} } {2} \]
where

\(\color{thistle}{a} = 25 \)

\( \color{royalblue}{b} = 13 \)

\( \color{palegreen}{c} = 8 \)

Answer 4

so we have,
\[ S \scriptsize\text{emi perimeter} (\color{chocolate}{s}) = \frac { \color{thistle}{25} + \color{royalblue}{13}+ \color{palegreen}{8} } {2} \rightarrow S \scriptsize\text{emi perimeter} (\color{chocolate}{s}) = \frac{46}{2} \rightarrow S \scriptsize\text{emi perimeter} (\color{chocolate}{s}) = \Large\text{23} \]

Answer 5

from here, we continue with heron's formula

\[ A = \sqrt{ \color{chocolate}{s}(\color{chocolate}{s}- \color{thistle}{a}) (\color{chocolate}{s}- \color{royalblue}{b} ) (\color{chocolate}{s}- \color{palegreen}{c} ) } \]
\( \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \updownarrow \)

\[ A = \sqrt{ \color{chocolate}{23}(\color{chocolate}{23}- \color{thistle}{25}) (\color{chocolate}{23}- \color{royalblue}{13} ) (\color{chocolate}{23}- \color{palegreen}{8} ) } \]

Answer 6

@BlueWarrior123 can you finish the rest?

Answer 7

\[ A = \sqrt{ \color{chocolate}{23} \times (-2) \times 10 \times 15 } \]
\( \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \updownarrow \)
\[ A = \Large\sqrt{(\color{steelblue}{-6900})} \]
\( \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \updownarrow \)
\[A = \Large \color{steelblue}{83.06} \; m^2 \]
:D

Answer 8

Is that the answer?

Answer 9

yes!

Answer 10

Thank you.

Answer 11

U CANT GIVE EXACT ANSWERS

Answer 12

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Florisalreadytaken
\[ A = \sqrt{ \color{chocolate}{23} \times (-2) \times 10 \times 15 } \]
\( \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \updownarrow \)
\[ A = \Large\sqrt{(\color{steelblue}{-6900})} \]
\( \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \updownarrow \)
\[A = \Large \color{steelblue}{83.06} \; m^2 \]
:D
\(\color{#0cbb34}{\text{End of Quote}}\)
no direct answers buddy

Answer 13

i explained the whole thing! even asked the dude to participate!

Answer 14

still gave a direct answer at the end