Question

Math problem help

Answer 1

so remember

if the roots of a quadratic function are a and b

then the quadratic function is

(x-a)(a-b) = 0

does that help you?

Answer 2

im sorry im a bit confused on what i may do with the function

Answer 3

oh, right

you just multiply it out

use the FOIL method

so that way then you can get it into the form of z^2 + az + b = 0

and then you can determine what a and b are

z is basically like 'x'

Answer 4

so think about it like this

if we had roots of 2 and 3

then our equation would be

(x-2)(x-3) = 0
x^2 -5x + 6 = 0

and so you could find out what the 'a' and b' value is if we're looking at

x^2 + ax + b = 0

Answer 5

(x-(-7+2i))(x-(-7-2i))=x^2+14x+53

Answer 6

and 14+53=67?

Answer 7

Well done!

Answer 8

:)