A bag contains 11 numbered chips inside. Two chips are labeled 1, three are labelled 2, and six are labelled 3. Let the random variable X = "number on a chip in the bag." What is the expected number of a chip that is randomly chosen from the bag?
For this question, we just have to find which chip has the highest probability. To find this, we just divide the number of chips labelled by the total amount of chips. For the two chips labelled "1", we can use 2/11 to figure out the percentage of probability. And then just repeat the same process for "2" and "3".
so what the answer
Here, I'll write the calculations and you solve them. Since two chips are labelled with "1", that means "1" will have the percentage of 2/11. Now just put that into a calculator and times it by 100 and you'll have a percentage. Since three chips are labelled "2", our percentage for "2" is 3/11. And finally, our last percentage is 6/11 for "3". Now just solve those, and see which one has the highest percentage.
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