Question

(5c-4)(8c+3)

Answer 1

5c(8c+3)- 4(8c+3)
40c^2+15c-32c-12=?

Answer 2

Distribute;
\[(5c-4)(8c+3)\]
\[5 c ( 8 c+ 3 ) − 4 ( 8 𝑐 + 3 )\]

Distribute a 2nd Time;
\[5𝑐(8𝑐+3)−4(8𝑐+3)\]
\[4 0 𝑐^2 + 1 5 𝑐 − 4 ( 8 𝑐 + 3 )\]

One more time;
\[4 0 𝑐 2 + 1 5 𝑐 − 4 ( 8 𝑐 + 3 )\]
\[4 0 𝑐 2 + 1 5 𝑐 − 3 2 𝑐 − 1 2\]

Combine Like terms;
\[4 0 𝑐 2 + 1 5 𝑐 − 3 2 𝑐 − 1 2\]
\[4 0 𝑐 2 − 1 7 𝑐 − 1 2\]

Solved!
\[4 0 𝑐 2 − 1 7 𝑐 − 1 2\]
Let me know if you have anymore questions!
ℂ𝕣𝕖𝕖𝕕

Answer 3

That is supposed to be 40c^2, not 40c2, my apologies.
ℂ𝕣𝕖𝕖𝕕