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Using the information from the previous question, find the equation in standard form for the area of the fenced-in section in terms of the length of the field. (area = length • width)
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the length and width added together would be the answer for the area.
So, what is the length and width added together?
you know area = length • width length = x - 200 width = x - 300 area = ?
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area = (x-200)(x-300) = ?
60000
@jhonyy9 wrote:
area = (x-200)(x-300) = ?
Correct answer: y= (x − 200)(x − 300) = x2 − 300x − 200x + 60,000 = x2 − 500x + 60,000
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