This object is composed of a cylinder of diameter 4 cm and height 14 cm on top of another cylinder of diameter 12 cm and height 4 cm. Determine the surface area of the object, to the nearest square centimeter.

Question

Ashely · Answer

do you possibly have a pic

surjithayer · Answer

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surface areaof smaller cylinder$$=2\pi r1h+\pi (r1)2 ^2$$
$$=2\pi (2)(14)+\pi(2)^2$$
$$=56 \pi+4\pi $$
$$=60 \pi$$
$$surface~area~of~bigger~cylinder =2 \pi r2h+2 (\pi (r2)^2)-\pi (r1)^2$$
$$=2 \pi (6)(4)+2 \pi (6)^2-\pi (2)^2$$
$$=48 \pi+72 \pi-4 \pi$$
$$=116 \pi$$
total surface area=?