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math problem
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@AZ
You need to know this rule \(\Large log ~(a) - log ~(b) = log (\frac{a}{b})\)
log(-2)-log(-7)
where did you get the -2 and -7 from? the fraction is 2/7
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log(2)-log(7)
there you go
thats all?
yes
wait
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it's \(\text{ln}\) which is \(\large log_e\)
so keep it as ln(2) - ln(7)
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