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klmjnmkj:
math problem
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klmjnmkj:
@AZ
AZ:
You need to know this rule \(\Large log ~(a) - log ~(b) = log (\frac{a}{b})\)
klmjnmkj:
log(-2)-log(-7)
AZ:
where did you get the -2 and -7 from? the fraction is 2/7
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klmjnmkj:
log(2)-log(7)
AZ:
there you go
klmjnmkj:
thats all?
AZ:
yes
AZ:
wait
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AZ:
it's \(\text{ln}\) which is \(\large log_e\)
AZ:
so keep it as ln(2) - ln(7)
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