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Mathematics
klmjnmkj:

math problem

klmjnmkj:

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klmjnmkj:

@AZ

AZ:

You need to know this rule \(\Large log ~(a) - log ~(b) = log (\frac{a}{b})\)

klmjnmkj:

log(-2)-log(-7)

AZ:

where did you get the -2 and -7 from? the fraction is 2/7

klmjnmkj:

log(2)-log(7)

AZ:

there you go

klmjnmkj:

thats all?

AZ:

yes

AZ:

wait

AZ:

it's \(\text{ln}\) which is \(\large log_e\)

AZ:

so keep it as ln(2) - ln(7)

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