A survey is conducted to determine if citizens will attend a fire safety meeting. The result of the 105 citizens surveyed showed that 33% will attend the fire safety meeting. Find the margin of error. A: ±1.5% B: ±33% C: ±9.8% D: ±1.0%
1 hour ago? lol btw, it is just asking for the margain of error? odd -- why did it give us the percentage result when we're just asked to find just the margin of error? we would only need that to find the confidence interval... neway. we know that the margain of error is equal to \[ \frac{100}{\sqrt{\color{lightskyblue}{n}}} \] where \[\text{nr of people surveyed}=\color{lightskyblue}{n} \] just do the math and you will have an answer
okay so I guess the answer is 9.8% because I got 9.75 which rounds up to 9.8 to the nearest tenth
pretty spot on
well I'll try that answer and see, I forgot to tell you I eliminated option B at the beginning because 33% is the amount of people that will attend the meeting, but nowhere near the margin of error
well yeah. my brain still cannot comprehend what whoever created this intended to do with that percentage.
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