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An integer is chosen at random from the first 40 positive integers. What is the probability that the integer chosen is divisible by 6 or 8? 9/40 1/4 11/40
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Well 8 16 24 32 40 6 12 18 24 30 36 and so we can cross of one of the 24 because there are 2 so we have 6, 8, 12, 16, 18, 24, 30, 32, 36, 40 which is 10 numbers
So we have 10/40 which simplifies to ->
1/4 ?
ye
1/4
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