Help (ss below)

Question

Help (ss below)

SunnyLandscape04 · Answer

attachment

Florisalreadytaken · Answer

is it asking for the overall area?

SunnyLandscape04 · Answer

attachment

Florisalreadytaken · Answer

yeah i was right

firstly, find the area of the triangle at the bottom and then the area of the 3 side trangles.

the formula you will be using is:
$$    \color{dodgerblue}{\triangle}\color{lightskyblue}{A} \color{lightskyblue}{\scriptsize\text{rea}} =\frac{\color{chocolate}{b} \times \color{teal}{h}} {2} $$

Florisalreadytaken · Answer

@bbxblue23 wrote:

ok you need to combine like terms (aka the 3's) then add the 2.6

??

Bbxblue23 · Answer

my sch

@florisalreadytaken wrote:

@bbxblue23 wrote:

ok you need to combine like terms (aka the 3's) then add the 2.6

??

my school has a different way of teaching- dont mind me :D

SunnyLandscape04 · Answer

I am still confused.

Florisalreadytaken · Answer

@florisalreadytaken wrote:

yeah i was right firstly, find the area of the triangle at the bottom and then the area of the 3 side trangles. the formula you will be using is: [color= inherit;][/color]$$ \color{dodgerblue}{\triangle}\color{lightskyblue}{A} \color{lightskyblue}{\scriptsize\text{rea}} =\frac{\color{chocolate}{b} \times \color{teal}{h}} {2} $$

for the base, it would be: $$ \color{dodgerblue}{\triangle}\color{lightskyblue}{A} \color{lightskyblue}{\scriptsize\text{rea}} =\frac{\color{chocolate}{3} \times \color{teal}{2.6}} {2} $$ whilst, for ALL 3 side ones it would be: $$ \color{dodgerblue}{\triangle}\color{lightskyblue}{A} \color{lightskyblue}{\scriptsize\text{rea}} = 3 \times \Big( \frac{\color{chocolate}{3} \times \color{teal}{3}} {2} \Big) $$

Florisalreadytaken · Answer

do the math, add it all together, and then comment in on here and i'll confirm whether its right or not.

SunnyLandscape04 · Answer

13.5?

MississippiMan22 · Answer

You can also do the 3x2.6 i think and then divide it by 2, that's how we learned

Florisalreadytaken · Answer

that's exactly what i did above lol

Florisalreadytaken · Answer

for base it would be:
$$ \color{dodgerblue}{\triangle}\color{lightskyblue}{Base A } \color{lightskyblue}{\scriptsize\text{rea}} = 3.9
  $$

for the other 3 sides, it would be:

$$   \color{dodgerblue}{\triangle}\color{lightskyblue}{Side A} \color{lightskyblue}{\scriptsize\text{rea}} = 13.5 $$

Florisalreadytaken · Answer

$$\color{dodgerblue}{\triangle}\color{lightskyblue}{Overall A } \color{lightskyblue}{\scriptsize\text{rea}} = 3.9+13.5=\underline{17.4}$$

SunnyLandscape04 · Answer

Okay, thank yu lol.

1 attachment

1 attachment