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So... Base side A is: 2 Base side B is: 2 Base side C is: 2 Height is: 3 Starting with the formulas: \[A=2A _{B}+(a+b+c)h\]\[A _{B}=\sqrt{s(s﹣a)(s﹣b)(s﹣c)}\]\[\frac{ a+b+c }{ 2 }\]
Literally as soon as I pinged flor you answered.
Alright, to solve for the surface area: \[A=ah+bh+ch+\frac{ 1 }{ 2 }\sqrt{-a^4+2(ab)^2+2(ac)^2-b^4+2(bc)^2-c^4}\]Then... \[=2*3+2*3+2*3+\frac{ 1 }{ 2 }*\sqrt{-2^4+2*(2*2)^2+2*(2*2)^2}-2^4+2*(2*2)^2-2^4\]
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