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@snowflake0531 I summon you B)
For the first one y=5x 3x-2y=14 Can you substitute the first equation into the second and solve for x? 3x-2(5x) = 14
@snowflake0531 wrote:
For the first one
y=5x
3x-2y=14
Can you substitute the first equation into the second and solve for x?
3x-2(5x) = 14
Yes and so what is x?
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-2
Now plug -2 into y=5x
-10
yes so (-2,-10)
@snowflake0531 wrote:
yes so (-2,-10)
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Now do the second one x - 2y = -2 y = 2x + 4 Can you try substitution the second equation into the first?
@snowflake0531 wrote:
Now do the second one
x - 2y = -2
y = 2x + 4
Can you try substitution the second equation into the first?
Uhm no you would do 2 -2(2x+4) = -2
@snowflake0531 wrote:
Uhm no
you would do
2 -2(2x+4) = -2
@zau31370 wrote:
@snowflake0531 wrote:
Uhm no
you would do
2 -2(2x+4) = -2
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SHoot i mean x-2(2x+4) = -2
@snowflake0531 wrote:
SHoot i mean
x-2(2x+4) = -2
No first do the distribution x-4x-8=-2
@snowflake0531 wrote:
No first do the distribution
x-4x-8=-2
It would be -2
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y = 2x + 4 so then put -2 into ^^^
ok so 2(-2) which is -4x+4 which is 0 right?
yes so (-2,0)
I think you should try the rest by yourself, isolate the x or y, substitute and find the variable
@snowflake0531 wrote:
I think you should try the rest by yourself, isolate the x or y, substitute and find the variable
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yes
k thank you snowflake
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