Ask your own question, for FREE!
Mathematics 8 Online
zau31370:

help, please

zau31370:

KjSaif:

@snowflake0531 I summon you B)

snowflake0531:

For the first one y=5x 3x-2y=14 Can you substitute the first equation into the second and solve for x? 3x-2(5x) = 14

zau31370:

@snowflake0531 wrote:
For the first one y=5x 3x-2y=14 Can you substitute the first equation into the second and solve for x? 3x-2(5x) = 14
yes, it will give you -7x=14

snowflake0531:

Yes and so what is x?

zau31370:

-2

snowflake0531:

Now plug -2 into y=5x

zau31370:

-10

snowflake0531:

yes so (-2,-10)

zau31370:

@snowflake0531 wrote:
yes so (-2,-10)
ok thank you may you help me with the other ones please

snowflake0531:

Now do the second one x - 2y = -2 y = 2x + 4 Can you try substitution the second equation into the first?

zau31370:

@snowflake0531 wrote:
Now do the second one x - 2y = -2 y = 2x + 4 Can you try substitution the second equation into the first?
well it be 2x+4-2=-2

snowflake0531:

Uhm no you would do 2 -2(2x+4) = -2

zau31370:

@snowflake0531 wrote:
Uhm no you would do 2 -2(2x+4) = -2
aghh ok then you simplify it

zau31370:

@zau31370 wrote:
@snowflake0531 wrote:
Uhm no you would do 2 -2(2x+4) = -2
aghh ok then you simplify it
to -4x-8=-2 ?

snowflake0531:

SHoot i mean x-2(2x+4) = -2

zau31370:

@snowflake0531 wrote:
SHoot i mean x-2(2x+4) = -2
-2x-4=-2 ? i think

snowflake0531:

No first do the distribution x-4x-8=-2

zau31370:

@snowflake0531 wrote:
No first do the distribution x-4x-8=-2
-3x=8-2 which is 6 then divide it by 3 which is 2

snowflake0531:

It would be -2

snowflake0531:

y = 2x + 4 so then put -2 into ^^^

zau31370:

ok so 2(-2) which is -4x+4 which is 0 right?

snowflake0531:

yes so (-2,0)

snowflake0531:

I think you should try the rest by yourself, isolate the x or y, substitute and find the variable

zau31370:

@snowflake0531 wrote:
I think you should try the rest by yourself, isolate the x or y, substitute and find the variable
hmm ok if i need help may i text you and ask you

snowflake0531:

yes

zau31370:

k thank you snowflake

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!