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Which reason justifies the last step in a proof that ∆EDG ≅ ∆ADC? Given: , D is the midpoint of . CPCTC ASA Postulate AAS Theorem SAS Postulate
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here is the ss
What are you 𝙩𝙝𝙞𝙣𝙠𝙞𝙣𝙜 the answer can be?
sas
I would agree with the answer. 𝐷.) "𝑆𝐴𝑆 𝑃𝑜𝑠𝑡𝑢𝑙𝑎𝑡𝑒" Nice work!
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