Physics
qweqeeqw:

Pyrex = 9 x10^-6 Aluminum= 25 x10^-6 An aluminum cap which serves as a cover to a glass pyrex jar is tightly attached to the glass; To open the jar, it was exposed to a hot water bath and the temperature was noted at 70 Celsius. The inside diameter of the cap is 6.0 cm at 30 Celsius. Find the difference in radius (cm) that will result by this method

jhonyy9:

so we know that the cap is from aluminiu and original - initial has a diameter of 6,0 cm at 30 C° the hot water bath at temp. of 70 C° to open the jar what radius changes will result ? if i understand it correct

qweqeeqw:

Yes

Extrinix:

Pyrex (glass container) =$$9 \times 10^\text{-6}$$ Aluminum (lid) $$25 \times 10^\text{-6}$$ here you go jhonyy, I know that was kind of confusing on what Pyrex was, but nothing to worry about.

jhonyy9:

ok ty. but now we need get the dilatation of the glass at 70 C° when we know that iniitial has a diameetr of 6 cm at 30 C° but like an idea if the glass jar will be dilated so i think the aluminium cape will dilate too

qweqeeqw:

do you know how to solve it?

jhonyy9:

so idk. if the dilatation is proportional with the temperature changes ? if yes so i think than we can use the rule of 3 simple to get the diameter on 70 C°

qweqeeqw:

yes it is

jhonyy9:

jhonyy9:

@qweqeeqw wrote:
yes it is
do you know the rule of 3 simple ?

jhonyy9:

so in this way we can write 6 cm in 30 C° x cm in 70 C° - cross multiplie and calcule the x value x = ?

Extrinix:

Looks like you are correct on that jhonyy

jhonyy9:

ohh - tysm and from this calcule we can make the difference of diameters and so one the difference of radius too

jhonyy9:

@extrinix wrote:
Looks like you are correct on that jhonyy
good to hear in this way - tysm

jhonyy9:

@extrinix but what idk. these details with Pyrex and aluminium where we need using ?

Extrinix:

so at $$30°C$$ the lid is at 6.0 cm and using the 2 equations Pyrex (glass container) =$$9 \times 10^\text{-6}$$ Aluminum (lid) $$25 \times 10^\text{-6}$$ it wants you to find the difference from when it was $$30°C$$ to after it was put in a hot water bath, $$70°C$$, in radius/cm

jhonyy9:

so this mean that you need calcule these changes for every two material - glass container and aluminium in case of 70 C° yes ?

Extrinix:

yes.

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