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Mathematics

kekeman:

Math: https://snipboard.io/2Y1zog.jpg

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snowflake0531:

you have the adjacent side and the opposite side from the reference angle \[\sin(\theta) = \frac{ opposite }{ hypotenuse }\] \[\cos(\theta) = \frac{ adjacent }{ hypotenuse }\] \[\tan(\theta) = \frac{ opposite }{ adjacent }\] which trig ratio do you use

kekeman:
cos

@snowflake0531 wrote:

you have the adjacent side and the opposite side from the reference angle
\[\sin(\theta) = \frac{ opposite }{ hypotenuse }\] \[\cos(\theta) = \frac{ adjacent }{ hypotenuse }\] \[\tan(\theta) = \frac{ opposite }{ adjacent }\] which trig ratio do you use

snowflake0531:

uhhh are you sure? you have opposite and adjacent

kekeman:

Oh so we use tan

snowflake0531:

Yes so how would you set the equation up using tan |dw:1620839068923:dw|

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kekeman:
10 divided by tan 50 degrees

@snowflake0531 wrote:

Yes so how would you set the equation up using tan Created with RaphaëlReply Using Drawing

snowflake0531:

tan(50) = x/10 try again

kekeman:

Dang it i knew it was 10 tan 50°

snowflake0531:

lol

kekeman:

So it is 10 tan 50°

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snowflake0531:

positive

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