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kekeman:
Math: https://snipboard.io/2Y1zog.jpg
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snowflake0531:
you have the adjacent side and the opposite side from the reference angle \[\sin(\theta) = \frac{ opposite }{ hypotenuse }\] \[\cos(\theta) = \frac{ adjacent }{ hypotenuse }\] \[\tan(\theta) = \frac{ opposite }{ adjacent }\] which trig ratio do you use
kekeman:
cos
@snowflake0531 wrote:
you have the adjacent side and the opposite side from the reference angle
\[\sin(\theta) = \frac{ opposite }{ hypotenuse }\] \[\cos(\theta) = \frac{ adjacent }{ hypotenuse }\] \[\tan(\theta) = \frac{ opposite }{ adjacent }\] which trig ratio do you use
snowflake0531:
uhhh are you sure? you have opposite and adjacent
kekeman:
Oh so we use tan
snowflake0531:
Yes so how would you set the equation up using tan |dw:1620839068923:dw|
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kekeman:
10 divided by tan 50 degrees
@snowflake0531 wrote:
Yes so how would you set the equation up using tan Created with RaphaëlReply Using Drawing
snowflake0531:
tan(50) = x/10 try again
kekeman:
Dang it i knew it was 10 tan 50°
snowflake0531:
lol
kekeman:
So it is 10 tan 50°
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snowflake0531:
positive
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