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you have the adjacent side and the opposite side from the reference angle \[\sin(\theta) = \frac{ opposite }{ hypotenuse }\] \[\cos(\theta) = \frac{ adjacent }{ hypotenuse }\] \[\tan(\theta) = \frac{ opposite }{ adjacent }\] which trig ratio do you use
@snowflake0531 wrote:
you have the adjacent side and the opposite side from the reference angle
\[\sin(\theta) = \frac{ opposite }{ hypotenuse }\] \[\cos(\theta) = \frac{ adjacent }{ hypotenuse }\] \[\tan(\theta) = \frac{ opposite }{ adjacent }\] which trig ratio do you use
uhhh are you sure? you have opposite and adjacent
Oh so we use tan
Yes so how would you set the equation up using tan |dw:1620839068923:dw|
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@snowflake0531 wrote:
Yes so how would you set the equation up using tan Created with RaphaëlReply Using Drawing
tan(50) = x/10 try again
Dang it i knew it was 10 tan 50°
lol
So it is 10 tan 50°
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