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Is what i picked correct: https://snipboard.io/Z91yfO.jpg
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in my opion yes
Ok thank you
yes it think
i *
ok, so were given the hypotenuse and the angle \(\theta \) -- we have to find the opposite, which is \( BC \) the relationship we can create between the 3 is created by SOH: \[ \sin \theta = \frac{opposite}{hypotenuse} \] \[ \sin 35^\circ = \frac{opposite}{8} \] \[ opposite= \sin35^\circ \times 8 \] which can be differently expressed as: \[ opposite= 8 \times \sin35^\circ \] so you are indeed correct! well done!
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