Question

pls help
ss below

Answer 1

@hero

Answer 2

Yeah hero help the kid cheat on his test

Answer 3

its not a test

Answer 4

its a study guide

Answer 5

Then why's it timed?

Answer 6

literally, all of the assignments are, that's just the way the app works

Answer 7

can anyone help?

Answer 8

we're given \( 8x^2-9x=1 \overset{\text{compare it to} }{ =====\Rightarrow} ax^2+bx+c \)
what is
\[ a=? \]
\[ b=? \]
\[ c=? \]

the quadratic formula is in the form of \[ \frac{-b\pm\sqrt{b^2-4ac}}{2a} \]

after finding a,b and c plug the numbers in.

Answer 9

oh i forgot to mention, you know that we can turn:

\[ 8x^2-9x=1 \]
into
\[ 8x^2-9x-1=0 \]
right?

Answer 10

A:1
B:9
C:1 ?

Answer 11

A:8

Answer 12

yes thats right

Answer 13

Nono.

let me make it easier to understand
\[ 8x^2+(-9)x+(-1)=0 \]

Answer 14

yes i get that part its just the rest

Answer 15

you dont as the answer you gave about a, b and c is wrong -- the operators play the whole game -- make sure to determine the operators correctly -- so what is a, b and c? look above

Answer 16

B:-9
C:-1 right?

Answer 17

there you go!

how would you plug that information into \( \frac{-b\pm\sqrt{b^2-4ac}}{2a}
\) ?

Answer 18

\[\sqrt{-(9)-4(8)(-1)}\]

Answer 19

?

Answer 20

\(A=8\) right? cuz u did it wrong above!
\[ \frac{-(-9)\pm\sqrt{(-9)^2-4\times 8 \times -1}}{2 \times 8} ​\]
can you finish it off?

Answer 21

yes thank you so much

Answer 22

and yes A=8