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Please help, screenshot will be posted below
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second option
@snowflake0531
@sofia123 wrote:
second option
I'm starting to doubt that's it's the second option because I'm testing it
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Well, Then do that, Test them untill you find the one that fit's.
I tried, but neither of them worked, that's kind of weird I messed up somewhere I just don't know where
well I'm thinking the answer may be A
\[\begin{aligned}cosA &= \frac{b^2+c^2-a^2}{2bc}=\frac{3^2+6^2-4^2}{2\times3\times6}=0.806 \\A&=\cos^{-1}(0.806)\\&\approx36^0 \end{aligned}\]
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Try others
well then it would have to be B since that is the only option for 36 degrees for the A value
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