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well u round the number u get like the answer
or wait let me see
u div or x
Ok
d=20 ft r=20/2=10 ft \[reqd.~area=\frac{ \pi r^2 \theta }{ 360 }\] \[=\frac{ \pi \times 10^2 \times 38 }{ 360 }\approx =33.14~ft^2\] \[here ~\pi=3.14\]
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C
kekeman you did it?
Yes thank you
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