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I feel like the answer is B.) 70
Am i correct
\[ m\overset{\Huge\frown}{CE}=110^o \] \[ m\overset{\Huge\frown}{CBE}=360^o-110^\circ \Rightarrow 250^\circ \] \[ \angle CDE= \frac{1}{2}\left( m\overset{\Huge\frown}{CBE}- m\overset{\Huge\frown}{CE} \right) \] \[ \angle CDE= \frac{1}{2}\left( 250^\circ - 110^o \right) \] \[ \angle CDE= \frac{1}{2} \times 140^\circ \] well done : D -- youre correct
Frr B.) is the answer
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