Question

help ss is below

Answer 1

\( x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a} \)

when the equation is \( ax^2 + bx + c = 0\)

Answer 2

so for z^2 - 8z - 3 = 0

that means

a = 1
b = -8
c = -3

plug those numbers into the formula above