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A” finishes his work in 15 days while “B” takes 10 days. How many days will the same work be done if they work together?
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If A takes 15 days to finish his work then, A’s 1 day of work = 1/15 B’s 1 day of work = 1/10 Total work is done by A and B in 1 day = 1/15 + 1/10 If we use LCM(15, 10), we would get 1 day’s work of A and B =
would that be (2+3)/30
Yes so now 1 days of work would equal what?
1/6?
Yes correct so if A and B can finish the work in 6 days if they work together.
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