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An observer (O) is located 900 feet from a building (B). The observer notices a helicopter (H) flying at a 49° angle of elevation from his line of sight. How high is the helicopter flying over the building? You must show all work and calculations to receive full credit.
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@yassspoo can yu help me
beet
a right triangle youre given \( \theta \) and adjacent height (x) is the opposite leg of the triangle so, what are we going to use? SOH? CAH? TOA?
toa ?
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yes \[ \theta=49^\circ \] \[ adjacent=900 \] \[ opposite= x \] TOA \( \Rightarrow \tan \theta= \frac{opposite (x)}{adjacent} \) \[ \tan49^\circ = \frac{x}{900} \] \[ \tan49^\circ \times 900 =x \] can you work it out? use the website i told you about
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