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math again ss below ;-;
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\[5(2+u) -u = 10+4(u+1)\] Remember what I said last time \(a(b+c) = a(b)+a(c)\) So \[5(2) + 5(u) - u=10+4(u)+4(1)\\10+4u=14+4u\\10=14\] Is this true?
no
yeah so the first one has no solution for the second one \[3(x+2)+4=5(x-1)+x\] \[3(x) + 3(2)+4 = 5(x)+5(-1) + x \\3x+10=6x-5\\15=3x\\x=~?\]
5 right?
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yes
yuuh
thankss
yw~
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