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On a test, Leo is asked to completely factor the polynomial 3x3 – 3x + 5x2 – 5. He uses double grouping to get (x2 – 1)(3x + 5). Has he factored the polynomial completely? Explain.
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\[3x^3+5x^2-3x-5 = (x^2-1)(3x+5)\] and you're trying to figure out whether or not it's fully factored Hint: look at the \(x^2-1\) and use the \(a^2-b^2 = (a-b)(a+b)\) formula to expand it/factor it fully
so like a simple idea when the sum of free part of the terms equal zero from this result that this polynomial can divide by (x-1)
in this above wrote way we have +3 +5 -3-5 = +8-8 = 0
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