A group of engineering students constructs a potato cannon. The height, h meters, of a potato t seconds after it is shot from the cannon that is on the roof of a building is modeled by the equation. h= -5(t-2)^2 + 45 a) how high is the potato after 1 s? b)when does the potato reach its maximum height? what is the height? c) How long is the potato in the air?

Question

mhanifa · Answer

What do you know about the subject for a start? Any ideas?

Hajer · Answer

I know the maximum height of 45 m and the time is t=2

mhanifa · Answer

@hajer wrote:

I know the maximum height of 45 m and the time is t=2

This is for part B and its correct

Hajer · Answer

I'm done with all the parts except part c.

mhanifa · Answer

Do you know what to do for part A? t = 1, find h

Hajer · Answer

Yes, and it is 40

mhanifa · Answer

For part C you need to solve it when h = 0

mhanifa · Answer

You will get two solutions and the greater one is the answer

Hajer · Answer

Many thanks. :)

mhanifa · Answer

You are welcome!

mhanifa · Answer

Just to be clear: -5(t-2)^2 + 45 = 0

Hajer · Answer

Thank you :)

mhanifa · Answer

No problem and good luck with your assignment. I didn't have to help you much

Hajer · Answer

Thank you, Yes it was simple but you respond quickly!.