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Mathematics 19 Online
69781639:

By substituting x+2y=p in the equation(x+2y)(x+2y) + 3(x+2y)-4=0 ,solve the quadratic equation in p.Hence,find possible values of x+2y.If x-2y=4,find all the possible values of x and y.

purplerain:

@shadow

mhanifa:

First step: p^2 + 3p - 4 = 0, solve for p. Next step: Solve the systems based on the value of p. Let me know if further help is needed.

69781639:

Thanks tat will help me start from somewhere at least

mhanifa:

No problem. Happy to help further.

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