By substituting x+2y=p in the equation(x+2y)(x+2y) + 3(x+2y)-4=0 ,solve the quadratic equation in p.Hence,find possible values of x+2y.If x-2y=4,find all the possible values of x and y.

Question

purplerain · Answer

@shadow

mhanifa · Answer

First step:
p^2 + 3p  - 4 = 0, solve for p.
Next step:
Solve the systems based on the value of p.
Let me know if further help is needed.

69781639 · Answer

Thanks tat will help me start from somewhere at least

mhanifa · Answer

No problem. Happy to help further.