Question

On a coordinate plane, a parabola opens up. It goes through (negative 6, 0), has a vertex at (negative 2, negative 16), has a y-intercept at (0, negative 12), and goes through (2, 0).
What are the x-intercepts of the graph of the function f(x) = x2 + 4x – 12?

(–6, 0), (2,0)
(–2, –16), (0, –12)
(–6, 0), (–2, –16), (2, 0)
(0, –12), (–6, 0), (2, 0)

Answer 1

https://media.edgenuity.com/evresources/3109/3109-09/3109-09-02/3109-09-02-assessment/3109-09-02-05.png

Answer 2

this is timed

Answer 3

i dont understand
help

Answer 4

idk any of this

Answer 5

oh ok
get me someone who can
please

Answer 6

lol

Answer 7

who

Answer 8

anyone

Answer 9

um lets see

Answer 10

it timed so....

Answer 11

for my next one

Answer 12

idkkkkk