On a coordinate plane, a parabola opens up. It goes through (negative 6, 0), has a vertex at (negative 2, negative 16), has a y-intercept at (0, negative 12), and goes through (2, 0). What are the x-intercepts of the graph of the function f(x) = x2 + 4x – 12?

Question

On a coordinate plane, a parabola opens up. It goes through (negative 6, 0), has a vertex at (negative 2, negative 16), has a y-intercept at (0, negative 12), and goes through (2, 0).
What are the x-intercepts of the graph of the function f(x) = x2 + 4x – 12?
<img src="https://media.edgenuity.com/evresources/3109/3109-09/3109-09-02/3109-09-02-assessment/3109-09-02-05.png" alt="On a coordinate plane, a parabola opens up. It goes through (negative 6, 0), has a vertex at (negative 2, negative 16), has a y-intercept at (0, negative 12), and goes through (2, 0)."/>

helpandlearnandchat · Answer

x intercepts are the coordinates where the parabola crosses the x axis, so in this case it would be $(-6,0)and(2,0)$