On a coordinate plane, a parabola opens up. It goes through (negative 6, 0), has a vertex at (negative 2, negative 16), has a y-intercept at (0, negative 12), and goes through (2, 0). What are the x-intercepts of the graph of the function f(x) = x2 + 4x – 12?
x intercepts are the coordinates where the parabola crosses the x axis, so in this case it would be \((-6,0)and(2,0)\)
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