Question

Solve the system of equations.
x+2y+3z=3
−x+3y+2z=12
x+y+z=−2

Answer 1

I begin by eliminating x and adding
x+2y+3z=3
−x+3y+2z=12

Answer 2

Im not sure what to do after that

Answer 3

5y+5z=15
divide by 5
y+z=3
x+y+z=-2
x+3=-2
x=-2-3=-5
x=-5
from first eq.
-5+2y+3z==3
2y+3z=-3-5=-8
y+z=3
multiply by 2
2y+2z=6
2y+3z=-8
subtract
-z=6+8=14
z=-14
y+z=3
y+(-14)=3
y=3+14=17

x=-5
y=17
z=-14

Answer 4

i dont understand honestly