Question

Find the magnitude for the vector.

Answer 1

1. subtract tip minus tail coordinates to get the vector
2. sqrt(x^2 + y^2) (if you forget this formula, imagine the vector being the hypotenuse of a right triangle)

I'll do the first one and let you work on the second one

R<10,7>
S<-5,-3>

subtracting S-R gives us

<-15, -10>

so our "x" is = -15 and "y" is -10

sqrt(x^2 + y^2) = sqrt( (-15)^2 + (-10)^2)) = sqrt(325)

also 5sqrt(13) if they insist on simplifying

Answer 2

Second problem:

S - R ---> <-1 - 7, -10 - 2> = <-8, -12> try to take it from here

Answer 3

just remember, it's (second set of coordinates) - (first set of coordinates)

so if it's like vector AB it's B - A